signature.m ( File view )

• By yueqiaohuayuan 2014-11-17
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• Point(s)： 3
```			function [st, angle, x0, y0] = signature(b, varargin)
%SIGNATURE Computes the signature of a boundary.
%   [ST, ANGLE, X0, Y0] = SIGNATURE(B) computes the signature of a
%   given boundary, B, where B is an np-by-2 array (np > 2)
%   containing the (x, y) coordinates of the boundary ordered in a
%   clockwise or counterclockwise direction. The amplitude of the
%   signature as a function of increasing ANGLE is output in
%   ST. (X0,Y0) are the coordinates of the centroid of the
%   boundary. The maximum size of arrays ST and ANGLE is 360-by-1,
%   indicating a maximum resolution of one degree. The input must be
%   a one-pixel-thick boundary obtained, for example, by using the
%   function boundaries. By definition, a boundary is a closed
%   curve.
%
%   [ST, ANGLE, X0, Y0] = SIGNATURE(B) computes the signature, using
%   the centroid as the origin of the signature vector.
%
%   [ST, ANGLE, X0, Y0] = SIGNATURE(B, X0, Y0) computes the boundary
%   using the specified (X0, Y0) as the origin of the signature
%   vector.

%   Copyright 2002-2004 R. C. Gonzalez, R. E. Woods, & S. L. Eddins
%   Digital Image Processing Using MATLAB, Prentice-Hall, 2004
%   \$Revision: 1.6 \$  \$Date: 2003/11/21 14:46:47 \$

% Check dimensions of b.
[np, nc] = size(b);
if (np < nc | nc ~= 2)
error('B must be of size np-by-2.');
end

% Some boundary tracing programs, such as boundaries.m, end where
% they started, resulting in a sequence in which the coordinates
% of the first and last points are the same. If this is the case,
% in b, eliminate the last point.
if isequal(b(1, :), b(np, :))
b = b(1:np - 1, :);
np = np - 1;
end

% Compute parameters.
if nargin == 1
x0 = round(sum(b(:, 1))/np); % Coordinates of the centroid.
y0 = round(sum(b(:, 2))/np);
elseif nargin == 3
x0 = varargin{
1
};
y0 = varargin{
2
};
else
error('Incorrect number of inputs.');
end

% Shift origin of coord system to (x0, y0)).
b(:, 1) = b(:, 1) - x0;
b(:, 2) = b(:, 2) - y0;

% Convert the coordinates to polar.  But first have to convert the
% given image coordinates, (x, y), to the coordinate system used by
% MATLAB for conversion between Cartesian and polar cordinates.
% Designate these coordinates by (xc, yc). The two coordinate systems
% are related as follows:  xc = y and yc = -x.
xc = b(:, 2);
yc = -b(:, 1);
[theta, rho] = cart2pol(xc, yc);

% Convert angles to degrees.
theta = theta.*(180/pi);

% Convert to all nonnegative angles.
j = theta == 0; % Store the indices of theta = 0 for use below.
theta = theta.*(0.5*abs(1 + sign(theta)))...
- 0.5*(-1 + sign(theta)).*(360 + theta);
theta(j) = 0; % To preserve the 0 values.

temp = theta;
% Order temp so that sequence starts with the smallest angle.
% This will be used below in a check for monotonicity.
I = find(temp == min(temp));

% Scroll up so that sequence starts with the smallest angle.
% Use I(1) in case the min is not unique (in this case the
% seq
...
...
```
...
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• 冈萨雷斯数字图像处理
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