im2jpeg2k.m ( File view )

  • By yueqiaohuayuan 2014-11-17
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			function y = im2jpeg2k(x, n, q) 
%IM2JPEG2K Compresses an image using a JPEG 2000 approximation.
%   Y = IM2JPEG2K(X, N, Q) compresses image X using an N-scale JPEG
%   2K wavelet transform, implicit or explicit coefficient
%   quantization, and Huffman symbol coding augmented by zero
%   run-length coding. If quantization vector Q contains two
%   elements, they are assumed to be implicit quantization
%   parameters; else, it is assumed to contain explicit subband step
%   sizes.  Y is an encoding structure containing Huffman-encoded
%   data and additional parameters needed by JPEG2K2IM for decoding.
%
%   See also JPEG2K2IM.

%   Copyright 2002-2004 R. C. Gonzalez, R. E. Woods, & S. L. Eddins
%   Digital Image Processing Using MATLAB, Prentice-Hall, 2004
%   $Revision: 1.5 $  $Date: 2003/10/26 18:38:13 $

global RUNS

error(nargchk(3, 3, nargin));         % Check input arguments

if ndims(x) ~= 2 | ~isreal(x) | ~isnumeric(x) | ~isa(x, 'uint8')
   error('The input must be a UINT8 image.');   
end

if length(q) ~= 2 & length(q) ~= 3 * n + 1
   error('The quantization step size vector is bad.');  
end

% Level shift the input and compute its wavelet transform.
x = double(x) - 128;
[c, s] = wavefast(x, n, 'jpeg9.7');

% Quantize the wavelet coefficients.
q = stepsize(n, q);
sgn = sign(c);     sgn(find(sgn == 0)) = 1;     c = abs(c);
for k = 1:n
   qi = 3 * k - 2;
   c = wavepaste('h', c, s, k, wavecopy('h', c, s, k) / q(qi));
   c = wavepaste('v', c, s, k, wavecopy('v', c, s, k) / q(qi + 1));
   c = wavepaste('d', c, s, k, wavecopy('d', c, s, k) / q(qi + 2));
end
c = wavepaste('a', c, s, k, wavecopy('a', c, s, k) / q(qi + 3));
c = floor(c);       c = c .* sgn;

% Run-length code zero runs of more than 10. Begin by creating
% a special code for 0 runs ('zrc') and end-of-code ('eoc') and
% making a run-length table. 
zrc = min(c(:)) - 1;      eoc = zrc - 1;      RUNS = [65535];

% Find the run transition points: 'plus' contains the index of the
% start of a zero run; the corresponding 'minus' is its end + 1.
z = c == 0;                 z = z - [0 z(1:end - 1)];
plus = find(z == 1);        minus = find(z == -1);

% Remove any terminating zero run from 'c'.
if length(plus) ~= length(minus)
   c(plus(end):end) = [];      c = [c eoc];        
end

% Remove all other zero runs (based on 'plus' and 'minus') from 'c'.
for i = length(minus):-1:1
   run = minus(i) - plus(i);
   if run > 10
      ovrflo = floor(run / 65535);    run = run - ovrflo * 65535;
      c = [c(1:plus(i) - 1) repmat([zrc 1], 1, ovrflo) zrc ...
           runcode(run) c(minus(i):end)];
   end
end

% Huffman encode and add misc. informati
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